17
edits
Changes
Jump to navigation
Jump to search
Line 38:
Line 38: + + + + + + + + + + + + + + + + + + + + + + + + + + + + + + +
→Demos and usage examples
[-0.777688831121563, -0.7776888311215626]
[-0.777688831121563, -0.7776888311215626]
[0.22911205809043574, 0.2291120580904359]
[0.22911205809043574, 0.2291120580904359]
</source>
* '''Demo of ODE with a step input and initial conditions.'''
<source lang="octave">
## This is a demo of a second order transfer function and a unit step input.
## in laplace we would have 1 1
## _______________ * _____
## s^2 + sqrt(2)*s +1 s
##
## So the denominator is s^3 + sqrt(2) * s^2 + s
# and for laplace initial conditions area
## t(0)=0 t'(0) =0 and the step has initial condition of 1
## so we set t''(0)=1
## In the code we use diff(y,1)(0) == 0 to do t'(0)=0
##
## I know that all this can be done using the control pkg
## But I used this to verify that this solution is the
## same as if I used the control pkg.
## With this damping ratio we should have a 4.321% overshoot.
##
syms y(x)
de =diff(y, 3 ) +sqrt(2)*diff(y,2) + diff(y) == 0;
f = dsolve(de, y(0) == 0, diff(y,1)(0) == 0 , diff(y,2)(0) == 1)
ff=function_handle(rhs(f))
x1=0:.01:10;
y=ff(x1);
plot(x1,y)
grid minor on
</source>
</source>