JordiGH

Joined 15 November 2011
8 bytes added ,  20 March 2017
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Line 5: Line 5:
\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
</math>
</math>
Hello!
Anonymous user