JordiGH
Joined 15 November 2011
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\frac{-b \pm \sqrt{b^2 - 4ac}}{2a} | \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} | ||
</math> | </math> | ||
Hello! | |||
Latest revision as of 21:56, 29 January 2021
I'm Jordi Gutiérrez Hermoso. You may contact me at jordigh@octave.org. My personal website and blog are elsewhere.
Testing math:
Hello!