User talk:JordiGH: Difference between revisions

Latest revision as of 15:00, 11 September 2013

$\int _{a}^{b}f(x)dx=\sum _{x\in Z}\oint _{\partial x}\omega +2$

Revision as of 14:42, 11 September 2013 (edit) JordiGH (talk \| contribs) No edit summary ← Older edit		Latest revision as of 15:00, 11 September 2013 (edit) (undo) JordiGH (talk \| contribs) No edit summary
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	<math>\int_a^b f(x) dx = \sum_{x \in Z} \oint_{\partial x} \omega</math>		<math>\int_a^b f(x) dx = \sum_{x \in Z} \oint_{\partial x} \omega + 2</math>