User:JordiGH: Difference between revisions

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\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
</math>
</math>
Hello!

Revision as of 10:20, 20 March 2017

I'm Jordi Gutiérrez Hermoso. You may contact me at jordigh@octave.org. My personal website and blog are elsewhere.

Testing math:

Hello!