Difference between revisions of "User:JordiGH"

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\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
 
\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
 
</math>
 
</math>
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 +
Hello!

Latest revision as of 03:20, 20 March 2017

I'm Jordi Gutiérrez Hermoso. You may contact me at jordigh@octave.org. My personal website and blog are elsewhere.

Testing math:

Hello!